Question

An airport has runways only 145 m long. A small plane must reach a ground speed of 44 m/s before it can become airborne. What average acceleration must the plane’s engines provide if it is to take off safely from its airport?

Answer 1

The value is
`a = 6.676 \ m/s^2`

Step-by-step explanation:

From the question we are told that

The length of the runways is
`l =145 \ m`

The required ground of a small plane is
`v = 44 \ m/s`

Generally from kinematics equation

`v^2 = u^2 + 2as`

Here u is the initial speed of the plane which is 0 m/s

so

`44^2 = 0^2 + 2 * a* 145`

=>
`a = 6.676 \ m/s^2`