Answer:
15.4 lbs
Explanation:
Since the average of the top five is 13.3 this says that:
total weight of all the fish / 5 = 13.3 lbs
Therefore, the total weight of all five fish is equal to:
13.3 * 5 = 66.5
With this number, I subtracted all the other weights and found that the missing weight was:
15.4lbs.
Therefore, Wayne S. had the biggest fish weighing 15.4lbs