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2 votes
The average weight of the top 5 fish at a fishing tournament was 13.3 pounds. Some of the

weights of the fish are shown in the table.

The average weight of the top 5 fish at a fishing tournament was 13.3 pounds. Some-example-1

2 Answers

3 votes

Answer:

15.4

Explanation:

(14.2 + 13.4 + 12.1 + 11.4 + X) / 5 = 13.3

(51.1 + X) / 5 = 13.3

Cross:

51.1 + X = 66.5

then X = 66.5 - 51.1

= 15.4

User Michael Hoffman
by
5.3k points
3 votes

Answer:

15.4 lbs

Explanation:

Since the average of the top five is 13.3 this says that:

total weight of all the fish / 5 = 13.3 lbs

Therefore, the total weight of all five fish is equal to:

13.3 * 5 = 66.5

With this number, I subtracted all the other weights and found that the missing weight was:

15.4lbs.

Therefore, Wayne S. had the biggest fish weighing 15.4lbs

User Dmitry Katkevich
by
5.7k points
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