67.2k views
3 votes
A database system assigns a 32-character ID to each record, where each character is either a number from 0 to 9 or a letter from A to F. Assume that each number or letter is equally likely. Find the probability that at least 16 characters in the ID are numbers. Use a TI-83, TI-83 plus, or TI-84 calculator to find the probability.

User J Evans
by
8.2k points

1 Answer

4 votes

Answer:

0.948

Explanation:

Given that:

Number of character ID = 32

Numbers = 0 - 9 = 10

Alphabets = A - F = 6

Likelihood of each number or alphabet is equal

Probability that atleast 16 characters in the ID are numbers

Probability of success (p) = required outcome / Total possible outcomes

p = 10/(10 + 6) = 5/8

P(at least 16 numbers), similar to 1 - p(at most 15)

Using the specified calculator :

Binomcdf(number of trials, p, 15) = 0.0520

1 - 0.0520 = 0.948

User Breandan
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories