Question

A 1000-turn solenoid is 50 cm long and has a radius of 2.0 cm. It carries a current of 18.0 A. What is the magnetic field inside the solenoid near its center

Answer 1

The value is
`B =  0.0452 \  T`

Step-by-step explanation:

From the question we are told that

The number of turns is N = 1000

The length is L = 50 cm = 0.50 m

The radius is r = 2.0 cm = 0.02 m

The current is I = 18.0 A

Generally the magnetic field is mathematically represented as

`B = \mu_o  * (N )/(L)  *  I`

Here
`\mu_o` is the permeability of free space with value

`\mu_o  =  4\pi * 10^(-7) N/A^2`

So

`B =  4\pi * 10^(-7)  *   (1000)/(0.50) *  18.0`

=>
`B =  0.0452 \  T`