Question

Find the vertex of the function given below


`y = {x}^(2) - 6x + 1`
​

Answer 1

3,-10...........................

Answer 2

vertex = (3, - 8 )

Explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

`x_(vertex)` = -
`(b)/(2a)`

y = x² - 6x + 1 ← is in standard form

with a = 1 and b = - 6 , thus

`x_(vertex)` = -
`(-6)/(2)` = 3

Substitute x = 3 into the function for y

y = 3² - 6(3) + 1 = 9 - 18 + 1 = - 8

vertex = (3, - 8 )