Question

64x⁶-1
anyone asap please??​

Answer 1

`\bold{Hello!}\\\bold{Your~Answer~Is~Below!}`

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`\bold{Solution~Steps:}`

`1.)~Rewrite: 64x^6-1~as~(8x^3)^2-1^2`

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  `The~difference~of~squares~can~be~factored~using~the~rule:`

`a^2-b^2=(a-b)(a+b)`

`\bold{(8x^3-1)(8x^3+1)}`

`2.)~Rewrite:~8x^3-1~as~(2x)^3-1^3`

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  `The~difference~of~cubes~can~be~factored~using~the~rule:`

`a^3-b^3=(a-b)(a^2+ab+b^2)`

`\bold{(2x+1)(4x^2+2x+1}`

`3.)~Rewrite:~8x^3+1~as~(2x)^3+1^3`

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  `The~sum~of~cubes~can~be~factored~using~the~rule:`

`a^3+b^3=(a+b)(a^2-ab+b^2)`

`\bold{(2x+1)(4x^2-2x+1)}`

`4.)~Rewrite~the~complete~factored~expression:`

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  `The~following~polynomials~are~not~factored~since~they~do~not~have~any~rational~roots:`

`(4x^2-2x+1),~(4x^2+2x+1)`

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`\bold{Answers:}`

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  `Factored~Form:~\bold{(2x-1)(4x^2-2x+1)(2x+1)(4x^2+2x+1)}`

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  `Evaluated~Form:~\bold{(4x^2-1)((4x^2+1)^2-4x^2)}`

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`\bold{Hope~this~helps,}\\\bold{And~best~of~luck!}\\\\\bold{~~~-TotallyNotTrillex}`