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The table shows the amount of pet food in cups remaining in an automatic feeder as a function of the number of meals the feeder has dispensed.

Based on the table, which function models this situation?

The table shows the amount of pet food in cups remaining in an automatic feeder as-example-1
User Neurax
by
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2 Answers

4 votes

Answer:f(n)=-3+24

Explanation

Unit rate of the table is three therefore taking away 3 cups each time food is dispensed aka -3n. 24 represents the starting point. 21+3=24

User MarlonRibunal
by
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5 votes

Answer:

f(n) = -3n + 24

Explanation:

Let the function representing Number of meals and amount of Pet Food remaining is,

f(n) = an + b

Where a = number of meals dispensed

n = amount of Pet food per meal

b = Initial amount of Pet food

From the table attached,

For n = 1 and f(n) = 21,

21 = a(1) + b

a + b = 21 -----------(1)

For n = 3 and f(n) = 15,

15 = a(3) + b

3a + b = 15 -----------(2)

Equation (2) - equation (1),

(3a + b) - (a + b) = 15 - 21

a = -3

From equation (1),

-3 + b = 21

b = 24

Therefore, function will be,

f(n) = -3n + 24

User Wazery
by
4.9k points