Question

A velocity selector uses a fixed electric field of magnitude E and the magnetic field is varied to select particles of various energies. If the electric field strength is 2.2 x 104 N/C, what should be the value of the magnetic field (in tesla) to select protons of velocity 6.4 x 105 m/s

Answer 1

The value is
`B =   0.034 \  T`

Step-by-step explanation:

From the question we are told that

The electric field strength is
`E =  2.2*10^(4) \  N/C`

The velocity is
`v  = 6.4 *10^(5) \  m/s`

Generally the magnetic field is mathematically represented as

`B =  (E)/(v)`

=>
`B =  (2.2*10^(4))/(6.4 *10^(5))`

=>
`B =   0.034 \  T`