The question is incomplete, the complete question is;
A 8.00 L tank at 2.64 °C is filled with 9.82 g of chlorine pentafluoride gas and 10.1 g of dinitrogen difluoride gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank. Be sure your answers have the correct number of significant digits.
Answer:
See explanation for details
Step-by-step explanation:
Number of moles of N2F2 = mass/ molar mass
Molar mass of N2F2 = 66 g/mol
Number of moles = 10.1 g/66 = 0.15 moles
Number of moles of ClF5 = 9.82 g/130 g/mol= 0.08 moles
Molar mass of ClF5= 130g/mol
Total number of moles = 0.15 moles + 0.08 moles = 0.23 moles
Given that;
T= 2.64 °C + 273 = 275.64 K
n= 0.23 moles
R= 0.082 Latmmol-1K-1
V= 8.00 L
P= ??
From;
PV =nRT
P= nRT/V
P= 0.23 ×0.082 × 275.64/8.00
P= 0.65 atm
Mole fraction of N2F2= 0.15/0.23 = 0.65
Partial pressure = mole fraction × total pressure = 0.65 × 0.65 = 0.42 atm
Mole fraction of ClF5 = 0.08/0.23 = 0.35
Partial pressure of ClF5 = mole fraction × total pressure = 0.35 × 0.65 = 0.22 atm