Answer:
method 1 should be selected.
Step-by-step explanation:
for method 1:
p = 550000
a = 160000
s = 125000
I = 10%
n = 3 years
aw = -550000(a/p, 0.10,3)-160000+125000(a/f,0.10,3)
= -550000(0.4021)-160000+125000(0.3021)
= -221155-160000+37762.5
= -343.392.5 dollars
for method 2:
salvage value = 240000x1.35
= 324000
p= 830000
a = 120000
s = 324000
I = 0.10 or 10%
n = 3
aw = -830000(a/p,0.10,3)-120000+324000(a/f,10%,3)
= -830000(0.4021)-120000+324000(0.3021)
= -333743-120000+97880.4
= -355862.6 dollars
after comparing both values, method 1 is better