Answer:
The decision rule is
Reject the null hypothesis
The conclusion
There is sufficient evidence to conclude that mean daily consumption of regular-coffee drinkers greater than that of decaffeinated-coffee.
The p-value is

Explanation:
From the question we are told that
The first sample size is

The first sample mean is

The first sample standard deviation is

The second sample size is
The second sample mean is

The second sample standard deviation is

The level of significance is

The null hypothesis is

The alternative hypothesis is

Generally the test hypothesis is mathematically represented as

=>

=>
Generally the p-value is mathematically represented as

From the z table

So

From the value obtained we see that
hence
The decision rule is
Reject the null hypothesis
The conclusion
There is sufficient evidence to conclude that mean daily consumption of regular-coffee drinkers greater than that of decaffeinated-coffee