Answer:
Step-by-step explanation:
one mole of AgNO₃ reacts to inactivate one mole of enzyme
mg of enzyme in 10 mL = 3.4 x 10 mg = 34 mg .
required AgNO₃ = .134 x 10⁻⁶ mole
.134 x 10⁻⁶ mole AgNO₃ is required for inactivating 34 mg of enzyme
1 mole of AgNO₃ will be required for inactivating 34 / (.134 x 10⁻⁶ ) mg of enzyme
= 253.73 x 10⁶ mg of enzyme
= 253.73 x 10³ g of enzyme
Mol weight of enzyme = 253.73 x 10³ .