Answer:
1) 57°
2) 142°
3) 92°
4) 125°
5) 111°
6) 90°
Explanation:
Assuming the 2 lines that look parallel in all of these problems, are actually parallel...
m<1 = 57° They are the same angle
m<HJK = 142° (again, same angle)
m<ABC = (4x = 3x + 23) solve for x
x = 23, then substitute 23 for x
4(23) = 92°
m<MPQ = (3x + 50 = 5x). solve for x
x = 25, then substitute 25 for x
3(25) + 50 = 125°
m<3 = 111° They are the same angle
m<4 = 90° If one angle is 90° where the lines cross, all of the angles are 90°