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You are sitting on a Ferris wheel moving at a constant speed of 8 m/s. When you are at the bottom of the rotation, what is the normal force of the seat on you if you have a mass of 50 kg and the radius of the Ferris wheel is 10 m

User Bpn
by
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1 Answer

4 votes

Answer:

40N

Step-by-step explanation:

Formula for calculating normal force is expressed as:


F = ma\\since \ a = (v^2)/(r) \\F = (mv^2)/(r)

m is the mass of the body = 50kg

v is the velocity of the Ferris wheel = 8m/s

r is the radius of the Ferris wheel

Substitute into the formula:


F = (50 * 8)/(10)\\ F = (400)/(10)\\ F = 40N\\

Hence the normal force of the seat is 40N

User Shibli
by
7.9k points
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