Question

mastering physics Two stones are launched from the top of a tall building. One stone is thrown in a direction 30.0 ∘ above the horizontal with a speed of 18.0 m/s ; the other is thrown in a direction 30.0 ∘ below the horizontal with the same speed

Answer 1

The stone thrown upward lands farther away from the building.

Step-by-step explanation:

Given that,

Angle = 30° above the horizontal

Speed = 18.0 m/s

Angle = 30° below the horizontal

Suppose, Which stone lands farther away from the building ?

We need to find which stone lands farther away from the building

Using formula of range

`R=v_(x)t`

The horizontal velocity for the both stones is equal but the time will be different.

The time of stone thrown upward will be greater than that of downward.

Hence, The stone thrown upward lands farther away from the building.