Question

Jordan and Sarah started cycling at the same time from the same place in opposite directions Jorans average speed was 16km per hour. Sarah's average speed was 3 8/9m per second. both of them stopped cycling after 40 mins. How much further did Jordan cycle than Sarah? How far apart was Jordan from Sarah at the end of 40 mins?

pls have the right answer by tomorrow.

Answer 1

• 1,333 1/3 m ≈ 1.33 km farther
• 20 km separation

Explanation:

The answer to this involves the relation between time, speed, and distance, as well as a couple of conversion factors.

• distance = speed × time
• 1 km = 1000 m
• 1 h = 60 min
• 1 min = 60 s

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Jordan's distance

Using the above conversion factors with Jordan's time and speed, we can find the distance Jordan traveled to be ...

distance = speed × time

distance = (16 km/h) × (40 min) = (16×1000 m)/(60 min) × (40 min)

distance = 32000/3 m = 10,666 2/3 m

Sarah's distance

Using Sarah's time and speed, we find Sarah's distance to be ...

distance = (3 8/9 m/s) × (40 min) × (60 s)/(1 min) = (3 8/9)(2400) m

distance = 9333 1/3 m

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difference

The difference between Jordan's distance and Sarah's is ...

10,666 2/3 m -9,333 1/3 m = 1,333 1/3 m

Jordan cycled 1,333 1/3 meters farther than Sarah, about 1.33 km.

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separation

The two went in opposite directions, so their separation is the sum of the distances they traveled.

10,666 2/3 m +9,333 1/3 m = 20,000 m = 20 km

The two cyclists were 20 km apart at the end of 40 minutes.