Complete Question
The complete question is shown in the first uploaded image
Answer:
So the math expression is
![heat = ( 35. 7 KJ * 1900 \ gram )/( 1 \ gram )](https://img.qammunity.org/2021/formulas/chemistry/college/gll3z96xhki1hcfvw8ukiichyacyrckgfu.png)
Step-by-step explanation:
From the question we are told that
The heat released for 1 gram of reactant consumed is
![H = 37.5 \ KJ/g](https://img.qammunity.org/2021/formulas/chemistry/college/nxm1j1ypiuju7tuw7ncfqfpuohuxok58h8.png)
The mass of reactant considered is
![m = 1.9 \ kg = 1900 \ g](https://img.qammunity.org/2021/formulas/chemistry/college/6ptgjxrql95o5l64zj5wq50jmmqospj4xd.png)
So if
is produced for 1 gram
Then
x kJ is produced for 1900 g
=>
![x = ( 35. 7 KJ * 1900 \ gram )/( 1 \ gram )](https://img.qammunity.org/2021/formulas/chemistry/college/sgdv5icodxwboyqwtgvwh06e0vebyiqj9d.png)
So the heat released is
![heat = ( 35. 7 KJ * 1900 \ gram )/( 1 \ gram )](https://img.qammunity.org/2021/formulas/chemistry/college/gll3z96xhki1hcfvw8ukiichyacyrckgfu.png)