Question

Assume that the inspired air is dry air. The vapor pressure of 47 mmHg at 37°C corresponds to a volume and mass of liquid water. If the tidal volume is 500 mL and respiration rate is 12 min−1, how much water is lost from the body per day? Would you expect this to increase or decrease with activity?

Answer 1

Water lost per day will be "378 g".

Step-by-step explanation:

The volume of air expired per a day will be:

=
`12* 500`

=
`8640 \ L`

As we know,

The ideal gad law equation will be:

⇒
`PV = nRT`

⇒
`((47)/(760) )* 8640= n* 0.082* 310`

⇒
`n=21* 18`

⇒
`n=378 \ g`