Question

What is the maximum speed with which a 1200-kg car can round a turn of radius 92.0 m on a flat road if the coefficient of static friction between tires and road is 0.65

Answer 1

24.22m/s

Step-by-step explanation:

Given data

mass m= 1200kg

radius r=92m

coefficient of friction μ=0.65

We know that

F=mv2/r

F=μmg

mv2/r = μsmg

v^2/r = μsg

vmax = √(rμg)

Substituting our data we have

vmax=√(92*0.65*9.81)

vmax=√586.638

vmax=24.22m/s