Question

A beam of charged particles moving with a speed of 106 m/s enters a uniform magnetic field of 0.1 T at right angles to the direction of motion. If the particles move in a radius of 0.2 m, then calculate their period of motion.

Answer 1

The period of motion is 1.26x10⁻⁶ s.

Step-by-step explanation:

The period of motion can be found as follows:

`\omega = (2 \pi)/(T)`

Where:

ω is the angular speed

T is the period

The angular speed is related to tangential speed (v):

`v = \omega r`

r is the radius

Hence, the period is:

`T = (2 \pi r)/(v) = (2 \pi 0.2 m)/(10^(6) m/s) = 1.26 \cdot 10^(-6) s`

Therefore, the period of motion is 1.26x10⁻⁶ s.

I hope it helps you!