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A Navy Seal of mass 80 kg parachuted directly down into an enemy harbor. At one point while she was falling, the resistive force that air exerted on her was 520 N upward. What can you determine about her motion at this point in time

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Answer:

The Navy Seal is accelerating downwards at the rate of 3.3 m/s²

Step-by-step explanation:

Given;

mass of the Navy Seal, m = 80 kg

the upward resistive force on her, F = 520 N

Her net downward force is given by;


F_(net) = F_(down) - F_(up)\\\\F_(net) = (80*9.8) - 520\\\\F_(net) = 264 \ N

Her downward acceleration at this time is given by;

F = ma

a = F / m

a = 264 / 80

a = 3.3 m/s²

Therefore, the Navy Seal is accelerating downwards at the rate of 3.3 m/s²

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