Question

ou are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the ee of this solution

Answer 1

Complete Question

You are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the enantiomeric excess?

Answer:

The value is
`k  = 96 %`

Step-by-step explanation:

From the question we are told that

The percentage of enantiomer A is A = 98%

The percentage of enantiomer B is B = 2%

Generally the enantiomeric excess is mathematically represented as

`k  =  (A -B)/(A+B)  *  100`

=>
`k  =  (98 -2)/(98+2)  *  100`

=>
`k  = 96 %`