Question

Find the maximum frequency for a non distorted sine-wave output voltage of 12-V peak with an Op-Amp that has a slew rate of 1.5 V/micro seconds

Answer 1

The maximum frequency is approximately 20,000 Hz

Step-by-step explanation:

Given;

peak output voltage, V = 12 V

slew rate, = 1.5 V/μs

The slew rate is given by;

slew rate = 2πfV

where;

f is the maximum frequency given by;

`f = (slew \ rate)/(2\pi V)\\\\ f = (1.5 )/(\mu*2\pi *12)\\\\ f = (1.5 )/(10^(-6)*2\pi *12)\\\\f = 19891.79\\\\f = 20,000 \ Hz\\\\f = 20 \ kHz`

Therefore, the maximum frequency is approximately 20,000 Hz