Question

उक्त समयमा बसले कति दुरी पार गर्दछ ? Abusstarts from

rest. If the acceleration of the bus is 0.5m/s, what will be it's
ve ocity at the end of 2 minutes and what distance will it cover
during that time?​

Answer 1

The magnitude of the velocity will be 60 m/s.

The distance covered is 3,600 m

Explanation:

Constant Acceleration Motion

It's known as a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

If a is the constant acceleration, vo is the initial speed, vf the final speed, and t the time, the following relation applies:

`v_f=v_o+at`

The distance traveled by the object is calculated as:

`\displaystyle x=v_o.t+(a.t^2)/(2)`

The bus starts from rest, i.e. vo=0, the acceleration is a=0.5 m/s^2. The magnitude of the velocity at t=2 minutes = 120 seconds is:

`v_f=0+0.5\cdot 120=60 \ m/s`

The magnitude of the velocity will be 60 m/s.

The distance covered during that time is:

`\displaystyle x=0+(0.5\cdot 120^2)/(2)`

`\displaystyle x=(7,200)/(2)`

x = 3,600 m

The distance covered is 3,600 m