Question

I don’t even know where to start..

Answer 1

`\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}`

Actually Welcome to the Concept of the Quadratic Equations,

Here, we just use the Quadratic formula to get the roots, that is values of X, since it is an degree 2 variable, so it will have Pair of roots,

x = -b +- underoot b^2-4ac/2a

Hence, answer is +- √7

Answer 2

Given :-

`\bullet \: 3 {x}^(2) + 7 = 28`

To Find :-

• Solution of x.

Solution :-

`\longrightarrow3 {x}^(2) + 7 = 28`

`\longrightarrow3 {x}^(2) = 28 - 7`

`\longrightarrow3 {x}^(2) = 21`

`\longrightarrow{x}^(2) = 7`

`\longrightarrow \bf x = \pm√(7)`