Question

The radius of Mars is 3.4 x 10^6m and the period of Mars's rotation is 24 hours. What is the radial accelerations (in m/s^2) of an object on the ground at its equator?

A. 0.018m/s^2
B. 0.136m/s^2
C. 0.068m/s^2
D. 0.376m/s^2

Answer 1

Option A: 0.018m/s^2

Step-by-step explanation:

Formula for radial acceleration is;

α_r = ω²r

Now, ω = 2π/T

We're given T = 24 hours. Converting to seconds is; T = 24 × 60 × 60 seconds

ω = 2π/(24 × 60 × 60)

We are given radius = 3.4 × 10^(6) m

Thus;

α_r = (2π/(24 × 60 × 60))² × 3.4 × 10^(6)

α_r = 0.018 m/s²