Question

If m CDE=(3x+10)° m CDF=(x+25)°, and m EDF= 65°. Find m CDF​

Answer 1

m∠CDF + m∠EDF = ∠CDE

`x + 25° + 65° = 3x + 10`

`x + 90° = 3x + 10`

`90° = 3x + 10 - x`

`90° = 2x + 10`

`2x + 10 = 90`

`2x = 90 - 10`

`2x = 80`

`x = (80)/(2)`

`x = 40°`

m∠CDE

= 3 × 40 + 10

= 120 + 10

= 130°

Then , m∠CDF =

`x + 25 \\ = 40 + 25 \\ = 65°`

•°• m∠CDF = 65°