Question

A 1200 kg car accelerates from rest for 45 meters in 6.0 seconds. What is the net force on the car?​

Answer 1

Step-by-step explanation:

At first, you have to get the acceleration value from the given data.

`s=ut+(1)/(2)at^(2)`

s= 45m

u= 0 m/s

t = 6s

a = ?

45 = 0+ 0.5 × a × 6²

45 = 0.5 × 36 × a

45 = 18a

a = 2.5 m/s²

Now, you can use F=ma equation

F = ?

m = 1200kg

a = 2.5 m/s²

F = 1200 × 2.5

F = 3000 N