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In a right triangle, one leg (a) is 10 cm, and its hypotenuse (c) is 26 cm. Find b?​

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Answer:


\boxed {\tt b=24 \ centimeters}

Explanation:

This is a right triangle, so we can use Pythagorean Theorem.


a^2+b^2=c^2

a and b are the legs, while c is the hypotenuse.

One leg is 10 centimeters. The hypotenuse is 26 centimeters. Therefore,


a= 10 \ cm \\c= 26 \ cm


(10 \ cm )^2+b^2=(26 \ cm)^2

Solve the exponents.

  • (10 cm)²= 10 cm * 10 cm= 100 cm²


100 \ cm^2+b^2=(26 \ cm)^2

  • (26 cm)²= 26 cm * 26 cm= 676 cm²


100 \ cm^2+b^2=676 \ cm^2

Subtract 100 from both sides of the equation.


100 \ cm^2- 100 \ cm^2+b^2=676 \ cm^2- 100 \ cm^2


b^2=676 \ cm^2 - 100 \ cm^2


b^2= 576 \ cm^2

Take the square root of both sides of the equation.


√(b^2) =√(576 \ cm^2)


b=√(576 \ cm^2)


b= 24 \ cm

The other leg of the triangle is equal to 24 centimeters.

User Mark Plotnick
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