Question

PLEASE HELP

At a circus, a human cannonball is shot from a cannon at 15m/s at an angle of 40° above horizontal. She
leaves the cannon 2m off the ground and lands in a net 1m off the ground. What height does she reach?
How much ground distance does she cover?

Answer 1

Step-by-step explanation:

`a_(x)=0`
`v_(xo)= v_(o)cos(delta)t`
`a_(y)=-g`
`v_(yo)=sin`θ

X-direction | Y-direction

`x=x_o+v_(xo)t` ⇒
`x=v_(xo)cos(delta)t` |