Question

The length of a rectangle is three times its width.

If the perimeter of the rectangle is 56 yd, find its area.

Answer 1

147 yards

Explanation:

Use a system of equations

Let x be length of rectangle and y be width of rectangle

x = 3y

2x + 2y = 56

Substitute x = 3y into second equation, we have 2(3y) + 2y = 56. Combine like terms and we have 8y = 56. y = 7.

Substituting y = 7 into the first equation, we have x = 3(7), and x = 21.

Area is length times width, so area is 21 * 7 = 147

Answer 2

area= 147 yd

Explanation:

l= 21 yd

w= 7 yd

Formula: a=lxw (area=length x width)

a=21 x 7

21 x 7=147 yd