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4 votes
Solve for a and b
(6a-3)=(7b-10)

1 Answer

3 votes

Answer:

for A=
(7b-7)/(6) and for B=
(6a+7)/(7)

Explanation:

For A


\left(6a-3\right)=\left(7b-10\right)


6a-3+3=7b-10+3


6a=7b-7


(6a)/(6)=(7b)/(6)-(7)/(6)


a=(7b-7)/(6)

For B


\left(6a-3\right)=\left(7b-10\right)


7b-10=\left(6a-3\right)


7b-10=6a-3


7b-10+10=6a-3+10


7b=6a+7


(7b)/(7)=(6a)/(7)+(7)/(7)


b=(6a+7)/(7)

User Mayur Patil
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