Question

I have ADHD and cannot focus on this question, please help me

Pavan is on his high school bowling team and scores an average number of 135 pins per game. During the course of a match, he bowls 146 in the first game and 135 in the second game. In his third game, he bowled 8 less pins than in his forth game.
a.) Let p be the score Pavan scored in his forth game. Set up an equation that models this equation.
b.) What were Pavan's score in the third and forth game?

Answer 1

9514 1404 393, H76, 5668 8637 469

Answer:

a) (146 +135 +(p-8) +p)/4 = 135

b) 3rd game: 125.5; 4th game: 133.5

Explanation:

The average score is the sum of scores divided by the number of games.

We are told the 4th game score is p, and the third game score is p-8. So, the scores in the four games are ...

146, 135, p-8, p

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a) Their average is 135, so we have ...

(146 +135 +(p-8) +p)/4 = 135 . . game average

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b) Solving the equation, we get ...

273 +2p = 540 . . . . . . . . . . . . . multiply by 4, collect terms

2p = 267 . . . . . . . . . . . . . . . . . . subtract 273

p = 133.5 . . . . . . divide by 2

Then the third game score is p-8 = 133.5-8 = 125.5, and the fourth game score is 133.5

Pavan's scores in the 3rd and 4th games were 125.5 and 133.5, respectively.

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Comment on the question

Of course, these scores make no sense as bowling scores.