Answer:
Yes
Step-by-step explanation:
The given parameters are;
The speed with which the fastball is hit, u = 49.1 m/s (109.9 mph)
The angle in which the fastball is hit, θ = 22°
The distance of the field = 96 m (315 ft)
The range of the projectile motion of the fastball is given by the following formula
![Range = (u^2 * sin(2\cdot \theta))/(g)](https://img.qammunity.org/2021/formulas/physics/high-school/jtyrztz4k3uw8k8bdtcf5le9mk99k2rbeu.png)
Where;
g = The acceleration due to gravity = 9.81 m/s², we have;
![Range = (49.1^2 * sin(2*22^(\circ)))/(9.81) \approx 170.71 \ m](https://img.qammunity.org/2021/formulas/physics/high-school/fhpurcmabcaj7tbsnbpaezduylddhuwhpz.png)
Yes, given that the ball's range is larger than the extent of the field, the batter is able to safely reach home.