Question

I will KISS U ON THE MOUTH IF U HURRY PLS HELP find the derivative dy/dx for y=(x^2+4x) / (x^3-5)

Answer 1

Use the quotient rule:

`(\mathrm dy)/(\mathrm dx)=((x^3-5)(\mathrm d(x^2+4x))/(\mathrm dx)-(x^2+4x)(\mathrm d(x^3-5))/(\mathrm dx))/((x^3-5)^2)`

`(\mathrm dy)/(\mathrm dx)=((2x+4)(x^3-5)-3x^2(x^2-4x))/((x^3-5)^2)`

`(\mathrm dy)/(\mathrm dx)=-(x^4 - 16 x^3 + 10 x + 20)/((x^3-5)^2)`