Question

Calculate the energy of a photon of light with a frequency of 6.17 x 1014 Hz.

Answer 1

The answer is

`\huge 4.088 * {10}^( - 19) \:J`

Step-by-step explanation:

The energy of a photon of light can be found by using the formula

E = hf

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 6.17 × 10¹⁴ Hz

We have

E = 6.17 × 10¹⁴ × 6.626 × 10-³⁴

We have the final answer as

`4.088 * {10}^( - 19) \: \: J`

Hope this helps you