Answer:
215.51 g of O2.
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KClO3 —> 2KCl + 3O2
Next, we shall determine the mass of KClO3 that decomposed and the mass of O2 produced from the balanced equation. This is illustrated below:
Molar mass of KClO3 = 39 + 35.5 + (16×3)
= 39 + 35.5 + 48
= 122.5 g/mol
Mass of KClO3 from the balanced equation = 2 × 122.5 = 245 g
Molar mass of O2 = 16 × 2 = 32 g/mol
Mass of O2 from the balanced equation = 3 × 32 = 96 g
From the balanced equation above,
245 g of KClO3 decomposed to produce 96 g of O2.
Finally, we shall determine the mass of O2 produced by the decomposition of 550 g of KClO3. This can be obtained as follow:
From the balanced equation above,
245 g of KClO3 decomposed to produce 96 g of O2.
Therefore, 550 g of KClO3 will decompose to produce =
(550 × 96)/245 = 215.51 g of O2.
Therefore, 215.51 g of O2 were obtained from the reaction.