Question

50.0 g of NaNO3 are dissolved into enough water to make 250 mL of solution. What is the molarity of this solution?

Answer 1

2.35 M

Step-by-step explanation:

Molarity is mol/L of solution. We have to convert the g to mol and the mL to L. G to mol uses the molar mass of the compound. The molar mass of NaNO₃ is 85.00g/mol.

`50.0gNaNO3*(1molNaNO3)/(85.00gNaNO3) = 0.588molNaNO3`

Then you have to convert mL to L.

`250mL*(1L)/(1000mL) = 0.250L`

Now divide the mol by the L.

`(0.588mol NaNO3)/(0.250L) = 2.352 M`

Round to the smallest number of significant figures = 2.35M