Question

45.0 g of CaCl, are dissolved in enough water so that the molarity of the solution is 1.15 M. What is the volume in mL of the solution?

Answer 1

CaCl calculate the molar mass of the compound first so u will get M.M=75.5 mol/g
Now multiple the mass of the compound by the molar mass ( make sure to cancel the mass unit so u get mole at the end)
45.0g x ( 1 mole:m/75.5g)
= 0.5960 mole
Now calculate the V
C= n/ V
V= n/c = 0.5960mole / 1.15 mol/ L = 0.6854 L
You are not done yet it asks for ml so multiple by 1000
685.43 ml
Now do sig fig
685 ml