Answer:
Acceleration, a = 9.877m/s²
Step-by-step explanation:
Given the following data;
Distance, d = 400m
Time, t = 9secs
Since it's starting from rest, initial velocity, u = 0
To solve for acceleration, we would use the second equation of motion;
![S = ut + \frac {1}{2}at^(2)](https://img.qammunity.org/2021/formulas/physics/high-school/nm8ircko4uqwxn46z4xnpwemvxjh5zbshj.png)
Substituting into the values into the equation;
![400 = 0(9) + \frac {1}{2}a(9)^(2)](https://img.qammunity.org/2021/formulas/physics/high-school/snt2ezgw9w986kccfkofk4gf6ltpeazx3y.png)
![400 = \frac {1}{2}a81](https://img.qammunity.org/2021/formulas/physics/high-school/npu12i4a0mznua75w9kqz4szpli9kqtb7p.png)
Cross multiplying, we have;
![a = \frac {800}{81}](https://img.qammunity.org/2021/formulas/physics/high-school/pe96y5f9yzyixhflu2b02pk8qewjjycq2m.png)
a = 9.877m/s²
Therefore, the automobile would have to accelerate at a constant rate of 9.877m/s²