Question

What is the force of a lead ball that starts with a momentum of 7 kg*m/s and end with a momentum of 22 kg*m/s over a time of 31 seconds?

Explain how you got your answer.

Answer 1

F = 0.483 N

Step-by-step explanation:

Initial momentum,
`P_i= 7\ kg-m/s`

Final momentum,
`P_f= 22\ kg-m/s`

Time, t = 31 s

We need to find the force of a lead ball. We can use here the impulse momentum theorem.

`\text{Change in momentum}=F* t`

F is force

`P_f-P_i=Ft\\\\F=(P_f-P_i)/(t)\\\\F=(22-7)/(31)\\\\F=0.483\ N`

So, the force is 0.483 N.