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find the point P along the directed line segment from point A(-11,1) to point B(0,-3) that divides the segment in the ratio 3 to 4

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Hi,

See the working out on the piece of paper and don’t hesitate to ask any questions if confused!!

find the point P along the directed line segment from point A(-11,1) to point B(0,-3) that-example-1
User Donlelek
by
7.9k points
9 votes

Answer:


\textsf{P}=\left(-(44)/(7),-(5)/(7)\right)

Explanation:

Given:

  • A = (-11, 1)
  • B = (0, -3)
  • Ratio 3 : 4

Therefore, point P on the segment AB should be 3/7 of the way from point A.


x_P=(3)/(7)(x_B-x_A)+x_A=(3)/(7)(0-(-11))-11=(-44)/(7)


y_P=(3)/(7)(y_B-y_A)+y_A=(3)/(7)(-3-1)+1=-(5)/(7)


\implies \textsf{P}=\left(-(44)/(7),-(5)/(7)\right)

or P = (-6.3, -0.7) to 1 decimal place

(Please see attached image, where the segment AB has been divided into 7 equal parts.)

find the point P along the directed line segment from point A(-11,1) to point B(0,-3) that-example-1
User Maninda
by
8.6k points

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