Question

An object accelerates from rest to a velocity of 34 m/s

over a distance of 70 m. What was its acceleration?

Answer 1

6.8m/s²

Step-by-step explanation:

Given parameters:

Initial velocity = 0m/s

Final velocity = 34m/s

Distance = 70m

Unknown:

To solve this problem we apply one of the motion equations;

V² = U² + 2aS

where V is the final velocity

U is the initial velocity

a is the acceleration

S is the distance covered

Input the parameters and solve;

34² = 0² + 2 x a x 70

34² = 140a

a = 6.8m/s²