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10 votes
10 votes
What is the distance between (0, 0) and (8, 15) on the
xy-coordinate plane?

User DarkTrick
by
2.8k points

1 Answer

8 votes
8 votes

Answer:

17

Explanation:


distance =\sqrt{(x2-x1) ^(2)+ (y2-y1) ^(2)}

Plug in (0,0) and (8,15):


distance =\sqrt{(8-0) ^(2)+ (15-0) ^(2)}\\\\= \sqrt{8^(2)+15^(2) } = √(64+225) = √(287) = 17

User MarioVilas
by
2.6k points