Question

What is the distance between (0, 0) and (8, 15) on the
xy-coordinate plane?

Answer 1

17

Explanation:

`distance =\sqrt{(x2-x1) ^(2)+ (y2-y1) ^(2)}`

Plug in (0,0) and (8,15):

`distance =\sqrt{(8-0) ^(2)+ (15-0) ^(2)}\\\\= \sqrt{8^(2)+15^(2) } = √(64+225) = √(287) = 17`