Question

Employees at a medical supply company are mixing saline solution for use in IVs. They start with 50 liters of 12% solution. To this, they plan to add 10% solution. How many liters of the 10% solution should they add in order to obtain a finished product that is 11% saline?

Answer 1

50 liters of the 10% solution should be added

Explanation:

Here, we want to calculate the number of liters of the 10% solution that should be added

Let the number of 10% solution to be added be x liters

So total liters is now x + 50

Thus;

50 liters of 12% + x liters of 10% = (x + 50) liters of 11 %

Hence

12/100 * 50 + 10/100 * x = 11/100 * (x + 50)

0.12(50) + 0.1(x) = 0.11(x + 50)

6 + 0.1x = 0.11x + 5.5

6 - 5.5 = 0.11x - 0.1x

0.5 = 0.01x

x = 0.5/0.01

x = 50