Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
The position of the emitter is
![E = + 72.9 \ cm\ from\ the\ center](https://img.qammunity.org/2021/formulas/mathematics/high-school/h5n04tfx00rwe48kzpcbge77m73qfrd43z.png)
The position of the stone is
![S = - 72.9 \ cm\ from\ the\ center](https://img.qammunity.org/2021/formulas/mathematics/high-school/o1l55bsl0kmfl1ithwqjab5wx96wtg8djj.png)
Explanation:
From the question we are told that
The length is l = 178 cm
The width is w = 102 cm
Generally the position of the stone along the horizontal axis is mathematically evaluated as
![h = (178)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/79c6aq3x2olfg3l9s6glo96yf61ki2cm5p.png)
=>
![h = 89 \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/crq7105tlrz36e813xi9o8wgau8xa3u369.png)
Generally the position of the emitter along the vertical axis is mathematically evaluated as
![k = (102)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/45hb5bbatllizwc73rvt308x50lratnkqh.png)
=>
Generally the resultant position of both stone and the emitter is
![R = \pm √(h^ 2 - k^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qgxpxlzdekfqgze8yel3au9318otzjodfa.png)
=>
![R = \pm √(89^ 2 - 51^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/isyqxszmfrst4j8wh5ff2u3kptslfr0v7h.png)
=>
![R = \pm 72.9 \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/vppepbg7re6b36y4o57bhtbszocizxxpqc.png)
Hence the position of the emitter is
![E = + 72.9 \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/tqj4kxh1l0kwvb25ys386wj0xu9l3q4puc.png)
the position of the stone is
![S = - 72.9 \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/qiis6qvmjbef9snn6xm2ff7mmj549zcy5z.png)