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A car moving with an intial velocity of 60m/s is brought to rest in 30 seconds calculate the acceleration

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Answer:

a = 2 [m/s^2]

Step-by-step explanation:

To solve this problem we must use the expressions of kinematics, we must bear in mind that when a body is at rest its velocity is zero.


v_(f) = v_(i) - (a*t)

where:

Vf = final velocity = 0

Vi = initial velocity = 60 [m/s]

a = desacceleration [m/s^2]

t = time = 30 [s]

Note: the negative sign of the above equation means that the car is slowing down, i.e. its speed decreases.

0 = 60 - (a*30)

a = 2 [m/s^2]

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