Answer:
Jody needs to lose the third round by 6 points to win the game.
Explanation:
The rule of the game is the person who scores closest to zero points after three rounds win.
Robyn scored 5 points in the first round, lost 8 points in the second round, and scored 4 points in the third round.
So, total points for Robyn = 5-8+4=1
So, the magnitude of the closeness of Robyn's score from zero
=|1-0|=1
Jody scored 10 points in the first round and lost 4 points in the second round.
Let Jody score x point in the third round.
Total points for Jody= 10-4+x=6+x
So, the magnitude of the closeness of Jody's score from zero
=|6+x-0|=|6+x|
The condition for Jody to win the game is his points must be closer to zero than Robyn's points, i.e
|6+x|<1
Case 1: If
,
6+x<1
, which is not possible for this case.
Case 2: If
,
-(6+x)<1
![\Rightarrow x>-5](https://img.qammunity.org/2021/formulas/mathematics/high-school/h2wwbza0eisdhvlt0zf1cnl2dk06ej5ny5.png)
For this case
is the only possibility.
So, Jody must score -6 in the third round to win the game. i.e Jody needs to lose the third round by 6 points.